更新
1.处理xml中的sql 获取最大委托编号问题
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@@ -256,14 +256,18 @@
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<!-- 取最大委托号, 目的是为了生成新的委托号 -->
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<select id="getMaxEntrustmentNo" parameterType="String" resultType="java.lang.String">
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SELECT MAX(entrustment_no) AS maxno
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SELECT entrustment_no
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FROM b_entrustment
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WHERE entrustment_no LIKE concat(#{prefix}, '%')
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WHERE entrustment_no LIKE CONCAT(#{prefix}, '%')
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ORDER BY CAST(SUBSTRING_INDEX(entrustment_no, '-', -1) AS UNSIGNED) DESC
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LIMIT 1
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</select>
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<select id="getMaxEntrustmentNoNew" parameterType="String" resultType="java.lang.String">
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SELECT MAX(entrustment_no) AS maxno
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SELECT entrustment_no
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FROM b_entrustment
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WHERE entrustment_no LIKE concat(#{prefix}, '%')
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WHERE entrustment_no LIKE CONCAT(#{prefix}, '%')
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ORDER BY CAST(SUBSTRING_INDEX(entrustment_no, '-', -1) AS UNSIGNED) DESC
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LIMIT 1
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</select>
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<select id="getMaxEntrustAcceptNo" parameterType="String" resultType="java.lang.String">
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SELECT MAX(CAST(SUBSTRING(accept_no, 6) AS UNSIGNED)) AS maxno
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